(3^x+3^x+3^x)/3=3^2

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Solution for (3^x+3^x+3^x)/3=3^2 equation: 



(3^x+3^x+3^x)/3=3^2

We move all terms to the left:

(3^x+3^x+3^x)/3-(3^2)=0

We add all the numbers together, and all the variables

(3^x+3^x+3^x)/3-9=0

We multiply all the terms by the denominator


(3^x+3^x+3^x)-9*3=0

We add all the numbers together, and all the variables

(3^x+3^x+3^x)-27=0

We get rid of parentheses

3^x+3^x+3^x-27=0

We move all terms containing x to the left, all other terms to the right

3^x+3^x+3^x=27

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